[Gameline146]

Greetings gents!

I am looking for a way to determine the % used of a specific volume.
using the df command shows me everything but i just need the percent used for a specific volme like /u01/help/me. I know i can get the one line by piping, but how would i extract that info?

I am basically looking to find this info so i can put it on the crontab and be notified when it exceeds a certain percentage.

[alexisl]

You can specify a specific mount-point/file system with df like:

df -g /etc

but I am not sure if that is what you want.

You can also use the du command to get the amount of space used by a specific directory or file like:

du -gs /etc/security

but it doesn't give percentages.

The best thing that I can tell you is to write a script using the du command if you actually need the percentage of use for a file/directory.

PS in both cases above the -g option is for display in Gigabytes

[Gameline146]

right. I can get the du to show me the size, but ita lso shows the directory as well. if I want to simply capture the value of the size into a script to do analysis on, how do I do that?

[alexisl]

I would write something like:

critical_level=1 #this is the level of use you are looking for in Gigabytes
use_level=`du -g /u01/help/me` #this gets the amount of use on the file specified

if [ $use_level <= $critical_level ]
then
mailx -s "Disk level critical" username@organization.com
fi

[FASherman]

du | grep | awk

[Gameline146]

here is the script
du -s /directory path | awk'
{
# load value from df command listing
#and comapre

if($1 > 6291456)
print "overload!"
[else
print "archiver ok"
]
}'
when executing i get this error:
crontab_archiver.shl[16]: awk^J{^J# load value from df command listing^J^Jif($1 > 6291456)^Jprint "overload!"^J[else^Jprint "archiver ok"^J]^J}: not found.


What am I doing wrong? If i just simply df and then sue awk to print $1, my return is the value i need.

[steevojb]

Hi There

TIMTOWTDI

du -s /directory/path | awk '
{
if ( $1 > 6291456 )
printf "overload!"
else
print "archiver OK"
}'


HTH

Steve

[Gameline146]

what if instead of a message, i wanted to mail the results with a messsage of something like "current usage is x% of total" or something similar?

[alexisl]

the mailx -s command will do that

mailx -s "subject here" emailaddress < input file with message

[Gameline146]

ok,

I tried some modifications to this and am getting some strange errors. I essentially want to build a file with the message that the size is too big, and send an email if the size is too large. The error I get is this:

Syntax Error The source line is 6.
The error context is
>>> else <<<
awk: 0602-502 The statement cannot be correctly parsed. The source line is 6.
Please remove log files to make space
Some parameters were not parsed.
Usage: no -h [tunable] | {-L [tunable]} | {-x [tunable]}
no [-p|-r] (-a | {-o tunable})
no [-p|-r] (-D | ({-d tunable} {-o tunable=value}))
NOTE:
1. The no commands can only be excuted by root.
2. -r, -p and -C flags must be placed at the beginning of the command line.
3. -r and -p are mutual exclusive.
4. Display (-a,-o option) and modification (-o option=value, -d option, -D) flags connot be mixed.
5. -D flag can not mixed with other modification (-o option=value, -d option) flags.


My original code is:

sendmail='no'
echo $Date > crontab_archiver.lis
echo "************************************************* " >> crontab_archiver.lis
du -s /path| awk '
{
if ( $1 > 6291456 )
printf "The archiver has exceeded capacity of x%." >> "crontab_archiver.lis"
sendmail ='yes'
else
print "archiver ok" >> "crontab_archiver.lis"
}'
echo "/n" >> crontab_archiver.lis
echo "Please remove log files to make space"
echo "********************************************* ***" >> crontab_archiver.lis
if $sendmail = 'yes'
then
echo mail -s "Archiver Overflow!" me@mail.com > crontab_archiver.lis
fi