[s.fida]

I need to create 7000 users for the new server. Our buissness rules sais that if the username is abcd1234 then the default password will be x1234. Is there any script that can do this which the script will read from a text files the usernames and their groups and creat the users with there proper password?


p.s. i do not know perl thats why im asking this question"

Shkumbin Fida.

[Gurft]

You could probably do this with a simple for loop in KSH

for i in $(cat usernames)
do
<mkuser command using the username>
<sed command to take the username and generate password>
echo "<username>:<password>" | chpasswd
done

[s.fida]

Gurf thanks for the post.
Gurf as i wrote it im not very familiar with such things. Ok if you dont mind it lets supose that my text file "usernames" has a raw as this:

ab123456 staff #(username and group).

What i do till now is like this.
mkuser pgrp=staff groups=staff ab123456
and i must put to times the password to change for each new users with command passwd.

So please can you define me the right syntax and your way of seting your commands in the for loop for the example that i write it. Remeber the password will take only the fourth characters of the username.

thanks in advance

[alexisl]

You could add something like this to what he said:

password=`echo $username|cut -c 5-8`

What this will do is echoing the username (I assume you will be reading it from a file) and then cutting the 5th through the 8th from the name and assigning them to a variable named password which you can use in the chpasswd command.

[s.fida]

As i saw it the easy way for me is to do this as follow
1. In a executable text file i can do a line from excell as follow:
mkuser pgrp=xxxx group=xxxxx ab123456

2. in another text file i can do as followed in step one
ab123456:2345

than running the command cat <filename> | chpasswd

After executing this two files ill have the users with thair passwords

thanks Gurf and Alexisl for telling me the command chpasswd (and olso man help)